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更新时间：2024-11-01 GMT+08:00
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案例：建立合适的索引

现象描述

查询与销售部所有员工的信息：

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--建表
CREATE TABLE staffs (staff_id NUMBER(6) NOT NULL, first_name VARCHAR2(20), last_name VARCHAR2(25), employment_id VARCHAR2(10), section_id NUMBER(4), state_name VARCHAR2(10), city VARCHAR2(10));
CREATE TABLE sections(section_id NUMBER(4), place_id NUMBER(4), section_name VARCHAR2(20));
CREATE TABLE states(state_id NUMBER(4));
CREATE TABLE places(place_id NUMBER(4), state_id  NUMBER(4));
--优化前查询
EXPLAIN SELECT staff_id,first_name,last_name,employment_id,state_name,city 
FROM staffs,sections,states,places 
WHERE sections.section_name='Sales' 
AND staffs.section_id = sections.section_id 
AND sections.place_id = places.place_id 
AND places.state_id = states.state_id 
ORDER BY staff_id;
--创建索引
CREATE INDEX loc_id_pk ON places(place_id);
CREATE INDEX state_c_id_pk ON states(state_id);
--优化后查询
EXPLAIN SELECT staff_id,first_name,last_name,employment_id,state_name,city 
FROM staffs,sections,states,places 
WHERE sections.section_name='Sales' 
AND staffs.section_id = sections.section_id 
AND sections.place_id = places.place_id 
AND places.state_id = states.state_id 
ORDER BY staff_id;

优化分析

在优化前，没有创建places.place_id和states.state_id索引，执行计划如下：

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                                             QUERY PLAN
----------------------------------------------------------------------------------------------------
 Sort  (cost=125.25..126.34 rows=438 width=254)
   Sort Key: staffs.staff_id
   ->  Hash Join  (cost=64.91..106.03 rows=438 width=254)
         Hash Cond: (states.state_id = places.state_id)
         ->  Seq Scan on states  (cost=0.00..29.45 rows=1945 width=12)
         ->  Hash  (cost=64.35..64.35 rows=45 width=266)
               ->  Hash Join  (cost=33.09..64.35 rows=45 width=266)
                     Hash Cond: (places.place_id = sections.place_id)
                     ->  Seq Scan on places  (cost=0.00..25.13 rows=1513 width=24)
                     ->  Hash  (cost=33.02..33.02 rows=6 width=266)
                           ->  Hash Join  (cost=19.16..33.02 rows=6 width=266)
                                 Hash Cond: (staffs.section_id = sections.section_id)
                                 ->  Seq Scan on staffs  (cost=0.00..12.76 rows=276 width=266)
                                 ->  Hash  (cost=19.11..19.11 rows=4 width=24)
                                       ->  Seq Scan on sections  (cost=0.00..19.11 rows=4 width=24)
                                             Filter: ((section_name)::text = 'Sales'::text)
(16 rows)

建议在places.place_id和states.state_id列上建立2个索引（参考现象描述），执行计划如下：

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                                             QUERY PLAN
-----------------------------------------------------------------------------------------------------
 Sort  (cost=107.40..108.49 rows=438 width=254)
   Sort Key: staffs.staff_id
   ->  Hash Join  (cost=35.37..88.18 rows=438 width=254)
         Hash Cond: (sections.section_id = staffs.section_id)
         ->  Nested Loop  (cost=19.16..66.85 rows=292 width=12)
               ->  Hash Join  (cost=19.16..50.27 rows=30 width=24)
                     Hash Cond: (places.place_id = sections.place_id)
                     ->  Seq Scan on places  (cost=0.00..25.13 rows=1513 width=24)
                     ->  Hash  (cost=19.11..19.11 rows=4 width=24)
                           ->  Seq Scan on sections  (cost=0.00..19.11 rows=4 width=24)
                                 Filter: ((section_name)::text = 'Sales'::text)
               ->  Index Only Scan using state_c_id_pk on states  (cost=0.00..0.45 rows=10 width=12)
                     Index Cond: (state_id = places.state_id)
         ->  Hash  (cost=12.76..12.76 rows=276 width=266)
               ->  Seq Scan on staffs  (cost=0.00..12.76 rows=276 width=266)
(15 rows)
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