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更新时间：2021-07-08 GMT+08:00
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编程实例

实例描述

本实例实现如下流程。

  1. 任务Example_TaskEntry创建一个互斥锁，锁任务调度，创建两个任务Example_MutexTask1、Example_MutexTask2。Example_MutexTask2优先级高于Example_MutexTask1，解锁任务调度，然后Example_TaskEntry任务休眠300Tick。
  2. Example_MutexTask2被调度，以永久阻塞模式申请互斥锁，并成功获取到该互斥锁，然后任务休眠100Tick，Example_MutexTask2挂起，Example_MutexTask1被唤醒。
  3. Example_MutexTask1以定时阻塞模式申请互斥锁，等待时间为10Tick，因互斥锁仍被Example_MutexTask2持有，Example_MutexTask1挂起。10Tick超时时间到达后，Example_MutexTask1被唤醒，以永久阻塞模式申请互斥锁，因互斥锁仍被Example_MutexTask2持有，Example_MutexTask1挂起。
  4. 100Tick休眠时间到达后，Example_MutexTask2被唤醒， 释放互斥锁，唤醒Example_MutexTask1。Example_MutexTask1成功获取到互斥锁后，释放锁。
  5. 300Tick休眠时间到达后，任务Example_TaskEntry被调度运行，删除互斥锁，删除两个任务。

编程示例

前提条件：通过make menuconfig完成互斥锁的配置。

代码实现如下：

/* 互斥锁句柄id */
UINT32 g_testMux;
/* 任务ID */
UINT32 g_testTaskId01;
UINT32 g_testTaskId02;

VOID Example_MutexTask1(VOID)
{
    UINT32 ret;

    printf("task1 try to get  mutex, wait 10 ticks.\n");
    /* 申请互斥锁 */
    ret = LOS_MuxPend(g_testMux, 10);

    if (ret == LOS_OK) {
        printf("task1 get mutex g_testMux.\n");
        /* 释放互斥锁 */
        LOS_MuxPost(g_testMux);
        return;
    } else if (ret == LOS_ERRNO_MUX_TIMEOUT ) {
            printf("task1 timeout and try to get mutex, wait forever.\n");
            /* 申请互斥锁 */
            ret = LOS_MuxPend(g_testMux, LOS_WAIT_FOREVER);
            if (ret == LOS_OK) {
                printf("task1 wait forever, get mutex g_testMux.\n");
                /* 释放互斥锁 */
                LOS_MuxPost(g_testMux);
                return;
            }
    }
    return;
}

VOID Example_MutexTask2(VOID)
{
    printf("task2 try to get  mutex, wait forever.\n");
    /* 申请互斥锁 */
    (VOID)LOS_MuxPend(g_testMux, LOS_WAIT_FOREVER);

    printf("task2 get mutex g_testMux and suspend 100 ticks.\n");

    /* 任务休眠100Ticks */
    LOS_TaskDelay(100);

    printf("task2 resumed and post the g_testMux\n");
    /* 释放互斥锁 */
    LOS_MuxPost(g_testMux);
    return;
}

UINT32 Example_TaskEntry(VOID)
{
    UINT32 ret;
    TSK_INIT_PARAM_S task1;
    TSK_INIT_PARAM_S task2;

    /* 创建互斥锁 */
    LOS_MuxCreate(&g_testMux);

    /* 锁任务调度 */
    LOS_TaskLock();

    /* 创建任务1 */
    memset(&task1, 0, sizeof(TSK_INIT_PARAM_S));
    task1.pfnTaskEntry = (TSK_ENTRY_FUNC)Example_MutexTask1;
    task1.pcName       = "MutexTsk1";
    task1.uwStackSize  = LOSCFG_BASE_CORE_TSK_DEFAULT_STACK_SIZE;
    task1.usTaskPrio   = 5;
    ret = LOS_TaskCreate(&g_testTaskId01, &task1);
    if (ret != LOS_OK) {
        printf("task1 create failed.\n");
        return LOS_NOK;
    }

    /* 创建任务2 */
    memset(&task2, 0, sizeof(TSK_INIT_PARAM_S));
    task2.pfnTaskEntry = (TSK_ENTRY_FUNC)Example_MutexTask2;
    task2.pcName       = "MutexTsk2";
    task2.uwStackSize  = LOSCFG_BASE_CORE_TSK_DEFAULT_STACK_SIZE;
    task2.usTaskPrio   = 4;
    ret = LOS_TaskCreate(&g_testTaskId02, &task2);
    if (ret != LOS_OK) {
        printf("task2 create failed.\n");
        return LOS_NOK;
    }

    /* 解锁任务调度 */
    LOS_TaskUnlock();
    /* 休眠300Ticks */
    LOS_TaskDelay(300);

    /* 删除互斥锁 */
    LOS_MuxDelete(g_testMux);

    /* 删除任务1 */
    ret = LOS_TaskDelete(g_testTaskId01);
    if (ret != LOS_OK) {
        printf("task1 delete failed .\n");
        return LOS_NOK;
    }
    /* 删除任务2 */
    ret = LOS_TaskDelete(g_testTaskId02);
    if (ret != LOS_OK) {
        printf("task2 delete failed .\n");
        return LOS_NOK;
    }

    return LOS_OK;
}

结果验证

编译运行得到的结果为：

task2 try to get  mutex, wait forever.
task2 get mutex g_testMux and suspend 100 ticks.
task1 try to get  mutex, wait 10 ticks.
task1 timeout and try to get mutex, wait forever.
task2 resumed and post the g_testMux
task1 wait forever,get mutex g_testMux.

完整实例代码

sample_mutex.c

父主题： 互斥锁

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