更新时间:2022-08-16 GMT+08:00

案例:设置cost_param对查询性能优化

现象描述

cost_param的bit0(set cost_param=1)值为1时,表示对于求!=连接的选择率时选择一种改良机制,此方法在自连接(两个相同的表之间连接)的估算中更加准确。下面查询的例子是cost_param的bit0为1时的优化场景。V300R002C00版本开始已弃用cost_param & 1不为0时的路径,默认选择已优化的估算公式。

注:选择率是两表join时,满足join条件的行数在join结果集中所占的比率。

表结构如下所示:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
CREATE TABLE LINEITEM
(
L_ORDERKEY BIGINT NOT NULL
, L_PARTKEY BIGINT NOT NULL
, L_SUPPKEY BIGINT NOT NULL
, L_LINENUMBER BIGINT NOT NULL
, L_QUANTITY DECIMAL(15,2) NOT NULL
, L_EXTENDEDPRICE DECIMAL(15,2) NOT NULL
, L_DISCOUNT DECIMAL(15,2) NOT NULL
, L_TAX DECIMAL(15,2) NOT NULL
, L_RETURNFLAG CHAR(1) NOT NULL
, L_LINESTATUS CHAR(1) NOT NULL
, L_SHIPDATE DATE NOT NULL
, L_COMMITDATE DATE NOT NULL
, L_RECEIPTDATE DATE NOT NULL
, L_SHIPINSTRUCT CHAR(25) NOT NULL
, L_SHIPMODE CHAR(10) NOT NULL
, L_COMMENT VARCHAR(44) NOT NULL
) with (orientation = column, COMPRESSION = MIDDLE) distribute by hash(L_ORDERKEY);

CREATE TABLE ORDERS
(
O_ORDERKEY BIGINT NOT NULL
, O_CUSTKEY BIGINT NOT NULL
, O_ORDERSTATUS CHAR(1) NOT NULL
, O_TOTALPRICE DECIMAL(15,2) NOT NULL
, O_ORDERDATE DATE NOT NULL
, O_ORDERPRIORITY CHAR(15) NOT NULL
, O_CLERK CHAR(15) NOT NULL
, O_SHIPPRIORITY BIGINT NOT NULL
, O_COMMENT VARCHAR(79) NOT NULL
)with (orientation = column, COMPRESSION = MIDDLE) distribute by hash(O_ORDERKEY);

查询语句如下所示:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
explain verbose select
count(*) as numwait 
from
lineitem l1,
orders 
where
o_orderkey = l1.l_orderkey
and o_orderstatus = 'F'
and l1.l_receiptdate > l1.l_commitdate
and not exists (
select
*
from
lineitem l3
where
l3.l_orderkey = l1.l_orderkey
and l3.l_suppkey <> l1.l_suppkey
and l3.l_receiptdate > l3.l_commitdate
)
order by
numwait desc;

执行计划如下图所示:(verbose条件下,新增distinct列,受cost off/on控制,hashjoin行显示内外表的distinct估值,其他行为空)

优化分析1

以上查询为lineitem表自连接的Anti Join,当使用cost_param的bit0为0时,估算Anti Join的行数与实际行数相差很大,导致查询性能下降。可以通过设置cost_param的bit0为1时,使Anti Join的行数估算更准确,从而提高查询性能。优化后的执行计划如下:

现象描述2

当cost_param的bit1(set cost_param=2)为1时,表示求多个过滤条件(Filter)的选择率时,选择最小的作为总的选择率,而非两者乘积,此方法在过滤条件的列之间关联性较强时估算更加准确。下面查询的例子是cost_param的bit1为1时的优化场景。

表结构如下所示:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
CREATE TABLE NATION
(
N_NATIONKEYINT NOT NULL
, N_NAMECHAR(25) NOT NULL
, N_REGIONKEYINT NOT NULL
, N_COMMENTVARCHAR(152)
) distribute by replication;
CREATE TABLE SUPPLIER
(
S_SUPPKEYBIGINT NOT NULL
, S_NAMECHAR(25) NOT NULL
, S_ADDRESSVARCHAR(40) NOT NULL
, S_NATIONKEYINT NOT NULL
, S_PHONECHAR(15) NOT NULL
, S_ACCTBALDECIMAL(15,2) NOT NULL
, S_COMMENTVARCHAR(101) NOT NULL
) distribute by hash(S_SUPPKEY);
CREATE TABLE PARTSUPP
(
PS_PARTKEYBIGINT NOT NULL
, PS_SUPPKEYBIGINT NOT NULL
, PS_AVAILQTYBIGINT NOT NULL
, PS_SUPPLYCOSTDECIMAL(15,2)NOT NULL
, PS_COMMENTVARCHAR(199) NOT NULL
)distribute by hash(PS_PARTKEY);

查询语句如下所示:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
set cost_param=2;
explain verbose select
nation,
sum(amount) as sum_profit 
from
(
select
n_name as nation,
l_extendedprice * (1 - l_discount) - ps_supplycost * l_quantity as amount
from
supplier,
lineitem,
partsupp,
nation
where
s_suppkey = l_suppkey
and ps_suppkey = l_suppkey
and ps_partkey = l_partkey
and s_nationkey = n_nationkey
) as profit 
group by nation 
order by nation;

当cost_param的bit1为0时,执行计划如下图所示:

优化分析2

在以上查询中,supplier、lineitem、partsupp三表做hashjoin的条件为(lineitem.l_suppkey = supplier.s_suppkey) AND (lineitem.l_partkey = partsupp.ps_partkey),此hashjoin条件中存在两个过滤条件,这前一个过滤条件中的lineitem.l_suppkey和后一个过滤条件中的lineitem.l_partkey同为lineitem表的两列,这两列存在强相关的关联关系。在这种情况,估算hashjoin条件的选择率时,如果使用cost_param的bit1为0时,实际是将AND的两个过滤条件分别计算的2个选择率的值相乘来得到hashjoin条件的选择率,导致行数估算不准确,查询性能较差。所以需要将cost_param的bit1为1时,选择最小的选择率作为总的选择率估算行数比较准确,查询性能较好,优化后的计划如下图所示: