更新时间:2022-06-13 GMT+08:00
分析函数
分析函数根据一组行计算一个聚合值。它与聚集函数的不同之处在于,它为每个组返回多行。分析函数通常用于计算累积值,数据移动值,中间值和报告聚合值。DSC支持分析函数,包括RATIO_TO_REPORT函数。
输入:分析函数
SELECT empno, ename, deptno , COUNT(*) OVER() AS cnt , AVG(DISTINCT empno) OVER (PARTITION BY deptno) AS cnt_dst FROM emp ORDER BY empno;
输出
WITH aggDistQuery1 AS ( SELECT deptno ,AVG ( DISTINCT empno ) aggDistAlias1 FROM emp GROUP BY deptno ) SELECT empno ,ename ,deptno ,COUNT( * ) OVER( ) AS cnt ,( SELECT aggDistAlias1 FROM aggDistQuery1 WHERE deptno = MigTblAlias.deptno ) AS cnt_dst FROM emp MigTblAlias ORDER BY empno ;
RATIO_TO_REPORT
RATIO_TO_REPORT是个分析函数,它会返回一个值与一组值的比例。
输入:RATIO_TO_REPORT
SELECT last_name, salary , RATIO_TO_REPORT(salary) OVER () AS rr FROM employees WHERE job_id = 'PU_CLERK';
输出
SELECT last_name, salary , salary / NULLIF( SUM (salary) OVER( ), 0 ) AS rr FROM employees WHERE job_id = 'PU_CLERK';
输入:RATIO_TO_REPORT,在SELECT中使用AGGREGATE列
SELECT Ename ,Deptno ,Empno ,SUM (salary) ,RATIO_TO_REPORT ( COUNT( DISTINCT Salary ) ) OVER( PARTITION BY Deptno ) RATIO FROM emp1 ORDER BY Ename ,Deptno ,Empno ;
输出
SELECT Ename ,Deptno ,Empno ,SUM (salary) ,COUNT( DISTINCT Salary ) / NULLIF( SUM ( COUNT( DISTINCT Salary ) ) OVER( PARTITION BY Deptno ) ,0 ) RATIO FROM emp1 ORDER BY Ename ,Deptno ,Empno ;
输入:RATIO_TO_REPORT,且AGGREGATE列使用扩展分组功能,但RATIO TO REPORT列的COUNT(Salary)不在SELECT字段列表中
可以使用extendedGroupByClause参数来配置扩展GROUP BY子句的迁移。
SELECT Ename ,Deptno ,Empno ,SUM (salary) ,RATIO_TO_REPORT ( COUNT( Salary ) ) OVER( PARTITION BY Deptno ) RATIO FROM emp1 GROUP BY GROUPING SETS ( Ename ,Deptno ,Empno ) ORDER BY Ename ,Deptno ,Empno ;
输出
SELECT Ename ,Deptno ,Empno ,ColumnAlias1 ,aggColumnalias1 / NULLIF( SUM ( aggColumnalias1 ) OVER( PARTITION BY Deptno ) ,0 ) RATIO FROM ( SELECT SUM (salary) AS ColumnAlias1 ,COUNT( Salary ) aggColumnalias1 ,NULL AS Deptno ,NULL AS Empno ,Ename FROM emp1 GROUP BY Ename UNION ALL SELECT SUM (salary) AS ColumnAlias1 ,COUNT( Salary ) aggColumnalias1 ,Deptno ,NULL AS Empno ,NULL AS Ename FROM emp1 GROUP BY Deptno UNION ALL SELECT SUM (salary) AS ColumnAlias1 ,COUNT( Salary ) aggColumnalias1 ,NULL AS Deptno ,Empno ,NULL AS Ename FROM emp1 GROUP BY Empno ) ORDER BY Ename ,Deptno ,Empno ;
父主题: 系统函数