Case: Rewriting SQL and Deleting Subqueries (1)
Symptom
1 2 3 4 |
select 1, (select count(*) from normal_date n where n.id = a.id) as GZCS from normal_date a; |
This SQL performance is poor. SubPlan exists in the execution plan as follows:
1 2 3 4 5 6 7 8 9 10 |
QUERY PLAN --------------------------------------------------------------------------------------------------------------------------------------- Seq Scan on normal_date a (cost=0.00..888118.42 rows=5129 width=4) (actual time=2.394..22194.907 rows=10000 loops=1) SubPlan 1 -> Aggregate (cost=173.12..173.12 rows=1 width=8) (actual time=22179.496..22179.942 rows=10000 loops=10000) -> Seq Scan on normal_date n (cost=0.00..173.11 rows=1 width=0) (actual time=11279.349..22159.608 rows=10000 loops=10000) Filter: (id = a.id) Rows Removed by Filter: 99990000 Total runtime: 22196.415 ms (7 rows) |
Optimization
The core of this optimization is to eliminate subqueries. Based on the service scenario analysis, a.id is not null. In terms of SQL syntax, you can rewrite the SQL statement as follows:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 |
select count(*) from normal_date n, normal_date a where n.id = a.id group by a.id; The plan is as follows: QUERY PLAN ---------------------------------------------------------------------------------------------------------------------------------- HashAggregate (cost=480.86..532.15 rows=5129 width=12) (actual time=21.539..24.356 rows=10000 loops=1) Group By Key: a.id -> Hash Join (cost=224.40..455.22 rows=5129 width=4) (actual time=6.402..13.484 rows=10000 loops=1) Hash Cond: (n.id = a.id) -> Seq Scan on normal_date n (cost=0.00..160.29 rows=5129 width=4) (actual time=0.087..1.459 rows=10000 loops=1) -> Hash (cost=160.29..160.29 rows=5129 width=4) (actual time=6.065..6.065 rows=10000 loops=1) Buckets: 32768 Batches: 1 Memory Usage: 352kB -> Seq Scan on normal_date a (cost=0.00..160.29 rows=5129 width=4) (actual time=0.046..2.738 rows=10000 loops=1) Total runtime: 26.844 ms (9 rows) |
To ensure that the modified statements have the same functions, NOT NULL is added to normal_date.id.
Feedback
Was this page helpful?
Provide feedbackThank you very much for your feedback. We will continue working to improve the documentation.See the reply and handling status in My Cloud VOC.
For any further questions, feel free to contact us through the chatbot.
Chatbot