How Do I Read Uploaded Files for a Spark Jar Job?

Updated on 2023-03-21 GMT+08:00

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You can use SparkFiles to read the file submitted using –-file form a local path: SparkFiles.get("Name of the uploaded file").

NOTE:

The file path in the Driver is different from that obtained by the Executor. The path obtained by the Driver cannot be passed to the Executor.
You still need to call SparkFiles.get("filename") in Executor to obtain the file path.
The SparkFiles.get() method can be called only after Spark is initialized.

Figure 1 Adding other dependencies
Click to enlarge

The java code is as follows:

package main.java
 
import org.apache.spark.SparkFiles
import org.apache.spark.sql.SparkSession
 
import scala.io.Source
 
object DliTest {
  def main(args:Array[String]): Unit = {
    val spark = SparkSession.builder
      .appName("SparkTest")
      .getOrCreate()
 
    // Driver: obtains the uploaded file.
    println(SparkFiles.get("test"))
 
    spark.sparkContext.parallelize(Array(1,2,3,4))
         // Executor: obtains the uploaded file.
      .map(_ => println(SparkFiles.get("test")))
      .map(_ => println(Source.fromFile(SparkFiles.get("test")).mkString)).collect()
  }
}

Parent topic: Job Development

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