date_sub
This function is used to calculate the number of days in which start_date is subtracted by days.
To obtain the date with a specified change range based on the current date, use this function together with the current_date or getdate function.
Note that the logic of this function is opposite to that of the date_add function.
Syntax
date_sub(string startdate, int days)
Parameters
Parameter |
Mandatory |
Type |
Description |
---|---|---|---|
start_date |
Yes |
DATE or STRING |
Start date The following formats are supported:
|
days |
Yes |
BIGINT |
Number of days to be reduced
|
Return Values
The return value is of the DATE type.
- If the value of start_date is not of the DATE or STRING type, the error message "data type mismatch" is displayed.
- If the value of start_date is of the DATE or STRING type but is not in one of the supported formats, NULL is returned.
- If the value of date is NULL, NULL is returned.
- If the value of format is NULL, NULL is returned.
Example Code
The value 2023-08-12 is returned after two days are subtracted.
select date_sub('2023-08-14 17:00:00', 2);
The value 2023-08-15 is returned after one day is added.
select date_sub(date'2023-08-14', -1);
If the current time is 2023-08-14 17:00:00, 2022-08-13 is returned.
select date_sub(getdate(),1);
The value NULL is returned.
select date_sub('2023-08-14 17:00:00', null);
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